Molar Mass of 1 Bromobutane
On the Molar Mass of Bromobutane
To understand the molar mass of bromobutane, it is necessary to analyze its molecular composition. The chemical formula of bromobutane is $C_ {4} H_ {9} Br $. The molar mass of
carbon ($C $) is about $12g/mol $, the molar mass of hydrogen ($H $) is about $1g/mol $, and the molar mass of bromine ($Br $) is about $80g/mol $.
In monobromobutane $C_ {4} H_ {9} Br $, it contains four atoms of carbon, so the total molar mass of carbon is 4 dollars\ times12g/mol = 48g/mol $; containing nine atoms of hydrogen, the total molar mass of hydrogen is 9 dollars\ times1g/mol = 9g/mol $; containing one atom of bromine, the molar mass of bromine is $80g/mol $.
Then the molar mass of monobromobutane is the sum of the molar masses of carbon, hydrogen and bromine, that is, $ (48 + 9 + 80) g/mol = 137g/mol $.
The molar mass of monobromobutane is of great significance in the fields of chemistry. For organic synthesis, it can be accurately calculated according to its molar mass to control the reaction process; for material analysis, it can also be an important basis for identification and purity determination.
